(h^2+M)=4N

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Solution for (h^2+M)=4N equation: 



(h^2+)=4

We move all terms to the left:

(h^2+)-(4)=0

We get rid of parentheses

h^2-4+=0

We add all the numbers together, and all the variables

h^2=0

a = 1; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·1·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$h=\frac{-b}{2a}=\frac{0}{2}=0$

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